3.18.61 \(\int \frac {(a+b x) (a^2+2 a b x+b^2 x^2)^{3/2}}{(d+e x)^{11}} \, dx\)

Optimal. Leaf size=254 \[ -\frac {3 b^2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^2}{4 e^5 (a+b x) (d+e x)^8}+\frac {4 b \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^3}{9 e^5 (a+b x) (d+e x)^9}-\frac {\sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^4}{10 e^5 (a+b x) (d+e x)^{10}}-\frac {b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{6 e^5 (a+b x) (d+e x)^6}+\frac {4 b^3 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)}{7 e^5 (a+b x) (d+e x)^7} \]

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Rubi [A]  time = 0.14, antiderivative size = 254, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {770, 21, 43} \begin {gather*} -\frac {b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{6 e^5 (a+b x) (d+e x)^6}+\frac {4 b^3 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)}{7 e^5 (a+b x) (d+e x)^7}-\frac {3 b^2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^2}{4 e^5 (a+b x) (d+e x)^8}+\frac {4 b \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^3}{9 e^5 (a+b x) (d+e x)^9}-\frac {\sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^4}{10 e^5 (a+b x) (d+e x)^{10}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((a + b*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(d + e*x)^11,x]

[Out]

-((b*d - a*e)^4*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(10*e^5*(a + b*x)*(d + e*x)^10) + (4*b*(b*d - a*e)^3*Sqrt[a^2 +
2*a*b*x + b^2*x^2])/(9*e^5*(a + b*x)*(d + e*x)^9) - (3*b^2*(b*d - a*e)^2*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(4*e^
5*(a + b*x)*(d + e*x)^8) + (4*b^3*(b*d - a*e)*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(7*e^5*(a + b*x)*(d + e*x)^7) - (
b^4*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(6*e^5*(a + b*x)*(d + e*x)^6)

Rule 21

Int[(u_.)*((a_) + (b_.)*(v_))^(m_.)*((c_) + (d_.)*(v_))^(n_.), x_Symbol] :> Dist[(b/d)^m, Int[u*(c + d*v)^(m +
n), x], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[b*c - a*d, 0] && IntegerQ[m] && ( !IntegerQ[n] || SimplerQ[c +
d*x, a + b*x])

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 770

Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dis
t[(a + b*x + c*x^2)^FracPart[p]/(c^IntPart[p]*(b/2 + c*x)^(2*FracPart[p])), Int[(d + e*x)^m*(f + g*x)*(b/2 + c
*x)^(2*p), x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && EqQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {(a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^{11}} \, dx &=\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {(a+b x) \left (a b+b^2 x\right )^3}{(d+e x)^{11}} \, dx}{b^2 \left (a b+b^2 x\right )}\\ &=\frac {\left (b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \frac {(a+b x)^4}{(d+e x)^{11}} \, dx}{a b+b^2 x}\\ &=\frac {\left (b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \left (\frac {(-b d+a e)^4}{e^4 (d+e x)^{11}}-\frac {4 b (b d-a e)^3}{e^4 (d+e x)^{10}}+\frac {6 b^2 (b d-a e)^2}{e^4 (d+e x)^9}-\frac {4 b^3 (b d-a e)}{e^4 (d+e x)^8}+\frac {b^4}{e^4 (d+e x)^7}\right ) \, dx}{a b+b^2 x}\\ &=-\frac {(b d-a e)^4 \sqrt {a^2+2 a b x+b^2 x^2}}{10 e^5 (a+b x) (d+e x)^{10}}+\frac {4 b (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2}}{9 e^5 (a+b x) (d+e x)^9}-\frac {3 b^2 (b d-a e)^2 \sqrt {a^2+2 a b x+b^2 x^2}}{4 e^5 (a+b x) (d+e x)^8}+\frac {4 b^3 (b d-a e) \sqrt {a^2+2 a b x+b^2 x^2}}{7 e^5 (a+b x) (d+e x)^7}-\frac {b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{6 e^5 (a+b x) (d+e x)^6}\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 162, normalized size = 0.64 \begin {gather*} -\frac {\sqrt {(a+b x)^2} \left (126 a^4 e^4+56 a^3 b e^3 (d+10 e x)+21 a^2 b^2 e^2 \left (d^2+10 d e x+45 e^2 x^2\right )+6 a b^3 e \left (d^3+10 d^2 e x+45 d e^2 x^2+120 e^3 x^3\right )+b^4 \left (d^4+10 d^3 e x+45 d^2 e^2 x^2+120 d e^3 x^3+210 e^4 x^4\right )\right )}{1260 e^5 (a+b x) (d+e x)^{10}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(d + e*x)^11,x]

[Out]

-1/1260*(Sqrt[(a + b*x)^2]*(126*a^4*e^4 + 56*a^3*b*e^3*(d + 10*e*x) + 21*a^2*b^2*e^2*(d^2 + 10*d*e*x + 45*e^2*
x^2) + 6*a*b^3*e*(d^3 + 10*d^2*e*x + 45*d*e^2*x^2 + 120*e^3*x^3) + b^4*(d^4 + 10*d^3*e*x + 45*d^2*e^2*x^2 + 12
0*d*e^3*x^3 + 210*e^4*x^4)))/(e^5*(a + b*x)*(d + e*x)^10)

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IntegrateAlgebraic [F]  time = 180.06, size = 0, normalized size = 0.00 \begin {gather*} \text {\$Aborted} \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[((a + b*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(d + e*x)^11,x]

[Out]

$Aborted

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fricas [A]  time = 0.43, size = 280, normalized size = 1.10 \begin {gather*} -\frac {210 \, b^{4} e^{4} x^{4} + b^{4} d^{4} + 6 \, a b^{3} d^{3} e + 21 \, a^{2} b^{2} d^{2} e^{2} + 56 \, a^{3} b d e^{3} + 126 \, a^{4} e^{4} + 120 \, {\left (b^{4} d e^{3} + 6 \, a b^{3} e^{4}\right )} x^{3} + 45 \, {\left (b^{4} d^{2} e^{2} + 6 \, a b^{3} d e^{3} + 21 \, a^{2} b^{2} e^{4}\right )} x^{2} + 10 \, {\left (b^{4} d^{3} e + 6 \, a b^{3} d^{2} e^{2} + 21 \, a^{2} b^{2} d e^{3} + 56 \, a^{3} b e^{4}\right )} x}{1260 \, {\left (e^{15} x^{10} + 10 \, d e^{14} x^{9} + 45 \, d^{2} e^{13} x^{8} + 120 \, d^{3} e^{12} x^{7} + 210 \, d^{4} e^{11} x^{6} + 252 \, d^{5} e^{10} x^{5} + 210 \, d^{6} e^{9} x^{4} + 120 \, d^{7} e^{8} x^{3} + 45 \, d^{8} e^{7} x^{2} + 10 \, d^{9} e^{6} x + d^{10} e^{5}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^11,x, algorithm="fricas")

[Out]

-1/1260*(210*b^4*e^4*x^4 + b^4*d^4 + 6*a*b^3*d^3*e + 21*a^2*b^2*d^2*e^2 + 56*a^3*b*d*e^3 + 126*a^4*e^4 + 120*(
b^4*d*e^3 + 6*a*b^3*e^4)*x^3 + 45*(b^4*d^2*e^2 + 6*a*b^3*d*e^3 + 21*a^2*b^2*e^4)*x^2 + 10*(b^4*d^3*e + 6*a*b^3
*d^2*e^2 + 21*a^2*b^2*d*e^3 + 56*a^3*b*e^4)*x)/(e^15*x^10 + 10*d*e^14*x^9 + 45*d^2*e^13*x^8 + 120*d^3*e^12*x^7
+ 210*d^4*e^11*x^6 + 252*d^5*e^10*x^5 + 210*d^6*e^9*x^4 + 120*d^7*e^8*x^3 + 45*d^8*e^7*x^2 + 10*d^9*e^6*x + d
^10*e^5)

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giac [A]  time = 0.20, size = 264, normalized size = 1.04 \begin {gather*} -\frac {{\left (210 \, b^{4} x^{4} e^{4} \mathrm {sgn}\left (b x + a\right ) + 120 \, b^{4} d x^{3} e^{3} \mathrm {sgn}\left (b x + a\right ) + 45 \, b^{4} d^{2} x^{2} e^{2} \mathrm {sgn}\left (b x + a\right ) + 10 \, b^{4} d^{3} x e \mathrm {sgn}\left (b x + a\right ) + b^{4} d^{4} \mathrm {sgn}\left (b x + a\right ) + 720 \, a b^{3} x^{3} e^{4} \mathrm {sgn}\left (b x + a\right ) + 270 \, a b^{3} d x^{2} e^{3} \mathrm {sgn}\left (b x + a\right ) + 60 \, a b^{3} d^{2} x e^{2} \mathrm {sgn}\left (b x + a\right ) + 6 \, a b^{3} d^{3} e \mathrm {sgn}\left (b x + a\right ) + 945 \, a^{2} b^{2} x^{2} e^{4} \mathrm {sgn}\left (b x + a\right ) + 210 \, a^{2} b^{2} d x e^{3} \mathrm {sgn}\left (b x + a\right ) + 21 \, a^{2} b^{2} d^{2} e^{2} \mathrm {sgn}\left (b x + a\right ) + 560 \, a^{3} b x e^{4} \mathrm {sgn}\left (b x + a\right ) + 56 \, a^{3} b d e^{3} \mathrm {sgn}\left (b x + a\right ) + 126 \, a^{4} e^{4} \mathrm {sgn}\left (b x + a\right )\right )} e^{\left (-5\right )}}{1260 \, {\left (x e + d\right )}^{10}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^11,x, algorithm="giac")

[Out]

-1/1260*(210*b^4*x^4*e^4*sgn(b*x + a) + 120*b^4*d*x^3*e^3*sgn(b*x + a) + 45*b^4*d^2*x^2*e^2*sgn(b*x + a) + 10*
b^4*d^3*x*e*sgn(b*x + a) + b^4*d^4*sgn(b*x + a) + 720*a*b^3*x^3*e^4*sgn(b*x + a) + 270*a*b^3*d*x^2*e^3*sgn(b*x
+ a) + 60*a*b^3*d^2*x*e^2*sgn(b*x + a) + 6*a*b^3*d^3*e*sgn(b*x + a) + 945*a^2*b^2*x^2*e^4*sgn(b*x + a) + 210*
a^2*b^2*d*x*e^3*sgn(b*x + a) + 21*a^2*b^2*d^2*e^2*sgn(b*x + a) + 560*a^3*b*x*e^4*sgn(b*x + a) + 56*a^3*b*d*e^3
*sgn(b*x + a) + 126*a^4*e^4*sgn(b*x + a))*e^(-5)/(x*e + d)^10

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maple [A]  time = 0.06, size = 201, normalized size = 0.79 \begin {gather*} -\frac {\left (210 b^{4} e^{4} x^{4}+720 a \,b^{3} e^{4} x^{3}+120 b^{4} d \,e^{3} x^{3}+945 a^{2} b^{2} e^{4} x^{2}+270 a \,b^{3} d \,e^{3} x^{2}+45 b^{4} d^{2} e^{2} x^{2}+560 a^{3} b \,e^{4} x +210 a^{2} b^{2} d \,e^{3} x +60 a \,b^{3} d^{2} e^{2} x +10 b^{4} d^{3} e x +126 a^{4} e^{4}+56 a^{3} b d \,e^{3}+21 a^{2} b^{2} d^{2} e^{2}+6 a \,b^{3} d^{3} e +b^{4} d^{4}\right ) \left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}}}{1260 \left (e x +d \right )^{10} \left (b x +a \right )^{3} e^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^11,x)

[Out]

-1/1260/e^5*(210*b^4*e^4*x^4+720*a*b^3*e^4*x^3+120*b^4*d*e^3*x^3+945*a^2*b^2*e^4*x^2+270*a*b^3*d*e^3*x^2+45*b^
4*d^2*e^2*x^2+560*a^3*b*e^4*x+210*a^2*b^2*d*e^3*x+60*a*b^3*d^2*e^2*x+10*b^4*d^3*e*x+126*a^4*e^4+56*a^3*b*d*e^3
+21*a^2*b^2*d^2*e^2+6*a*b^3*d^3*e+b^4*d^4)*((b*x+a)^2)^(3/2)/(e*x+d)^10/(b*x+a)^3

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^11,x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(a*e-b*d>0)', see `assume?` for
more details)Is a*e-b*d zero or nonzero?

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mupad [B]  time = 2.20, size = 449, normalized size = 1.77 \begin {gather*} \frac {\left (\frac {-4\,a^3\,b\,e^3+6\,a^2\,b^2\,d\,e^2-4\,a\,b^3\,d^2\,e+b^4\,d^3}{9\,e^5}+\frac {d\,\left (\frac {d\,\left (\frac {b^4\,d}{9\,e^3}-\frac {b^3\,\left (4\,a\,e-b\,d\right )}{9\,e^3}\right )}{e}+\frac {b^2\,\left (6\,a^2\,e^2-4\,a\,b\,d\,e+b^2\,d^2\right )}{9\,e^4}\right )}{e}\right )\,\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}}{\left (a+b\,x\right )\,{\left (d+e\,x\right )}^9}-\frac {\left (\frac {a^4}{10\,e}-\frac {d\,\left (\frac {d\,\left (\frac {d\,\left (\frac {2\,a\,b^3}{5\,e}-\frac {b^4\,d}{10\,e^2}\right )}{e}-\frac {3\,a^2\,b^2}{5\,e}\right )}{e}+\frac {2\,a^3\,b}{5\,e}\right )}{e}\right )\,\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}}{\left (a+b\,x\right )\,{\left (d+e\,x\right )}^{10}}-\frac {\left (\frac {6\,a^2\,b^2\,e^2-8\,a\,b^3\,d\,e+3\,b^4\,d^2}{8\,e^5}+\frac {d\,\left (\frac {b^4\,d}{8\,e^4}-\frac {b^3\,\left (2\,a\,e-b\,d\right )}{4\,e^4}\right )}{e}\right )\,\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}}{\left (a+b\,x\right )\,{\left (d+e\,x\right )}^8}+\frac {\left (\frac {3\,b^4\,d-4\,a\,b^3\,e}{7\,e^5}+\frac {b^4\,d}{7\,e^5}\right )\,\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}}{\left (a+b\,x\right )\,{\left (d+e\,x\right )}^7}-\frac {b^4\,\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}}{6\,e^5\,\left (a+b\,x\right )\,{\left (d+e\,x\right )}^6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*x)*(a^2 + b^2*x^2 + 2*a*b*x)^(3/2))/(d + e*x)^11,x)

[Out]

(((b^4*d^3 - 4*a^3*b*e^3 + 6*a^2*b^2*d*e^2 - 4*a*b^3*d^2*e)/(9*e^5) + (d*((d*((b^4*d)/(9*e^3) - (b^3*(4*a*e -
b*d))/(9*e^3)))/e + (b^2*(6*a^2*e^2 + b^2*d^2 - 4*a*b*d*e))/(9*e^4)))/e)*(a^2 + b^2*x^2 + 2*a*b*x)^(1/2))/((a
+ b*x)*(d + e*x)^9) - ((a^4/(10*e) - (d*((d*((d*((2*a*b^3)/(5*e) - (b^4*d)/(10*e^2)))/e - (3*a^2*b^2)/(5*e)))/
e + (2*a^3*b)/(5*e)))/e)*(a^2 + b^2*x^2 + 2*a*b*x)^(1/2))/((a + b*x)*(d + e*x)^10) - (((3*b^4*d^2 + 6*a^2*b^2*
e^2 - 8*a*b^3*d*e)/(8*e^5) + (d*((b^4*d)/(8*e^4) - (b^3*(2*a*e - b*d))/(4*e^4)))/e)*(a^2 + b^2*x^2 + 2*a*b*x)^
(1/2))/((a + b*x)*(d + e*x)^8) + (((3*b^4*d - 4*a*b^3*e)/(7*e^5) + (b^4*d)/(7*e^5))*(a^2 + b^2*x^2 + 2*a*b*x)^
(1/2))/((a + b*x)*(d + e*x)^7) - (b^4*(a^2 + b^2*x^2 + 2*a*b*x)^(1/2))/(6*e^5*(a + b*x)*(d + e*x)^6)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(b**2*x**2+2*a*b*x+a**2)**(3/2)/(e*x+d)**11,x)

[Out]

Timed out

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